4x^2=(2.9)(7.6-x)(-x)

Solution for 4x^2=(2.9)(7.6-x)(-x) equation:

4x^2=(2.9)(7.6-x)(-x)

We move all terms to the left:

4x^2-((2.9)(7.6-x)(-x))=0

We add all the numbers together, and all the variables

4x^2-((2.9)(-1x+7.6)(-1x))=0

We multiply parentheses ..

4x^2-((-2.9x+22.04)(-1x))=0


We calculate terms in parentheses: -((-2.9x+22.04)(-1x)), so:

(-2.9x+22.04)(-1x)

We multiply parentheses ..

(+2x^2-22.04x)

We get rid of parentheses

2x^2-22.04x

Back to the equation:

-(2x^2-22.04x)


We get rid of parentheses

4x^2-2x^2+22.04x=0

We add all the numbers together, and all the variables

2x^2+22.04x=0

a = 2; b = 22.04; c = 0;
Δ = b2-4ac
Δ = 22.042-4·2·0
Δ = 485.7616
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(22.04)-\sqrt{485.7616}}{2*2}=\frac{-22.04-\sqrt{485.7616}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(22.04)+\sqrt{485.7616}}{2*2}=\frac{-22.04+\sqrt{485.7616}}{4}
$